P = purple, pp = white. The offspring of a cross between two heterozygous purple-flowering plants (Pp × Pp) r

P = purple, pp = white. The offspring of a cross between two heterozygous purple-flowering plants (Pp × Pp) results in








a. all purple-flowered plants.





b. purple-flowered plants and white-flowered plants.





c. two types of white-flowered plants: PP and Pp.





d. all white-flowered plants.





e. all pink-flowered plants.

P = purple, pp = white. The offspring of a cross between two heterozygous purple-flowering plants (Pp × Pp) r
If we set up a punnet square, then we get:





___P__p


P PP Pp


p Pp pp





PP and Pp are purple flowered plants


pp is a white flowered plant





So we know it can't be a because we have white plants. B seems to work at this point. C can't be right because we know PP and Pp produce purple plants. Looking at D and E, we know they are wrong because we have purple flowers and no pink flowers. So the answers is . . .
Reply:Pardon my terminology, but look at your text book, dumbo. Think about it. If you have the question to list out in so specific of a form, it must have come from a text. The text will not require you to give an answer which they have not equipped you to do. Now in a Pp*Pp cross you can get_______





PP, Pp, Pp, and pp





Simple Punett square





Sorry for being so mean.
Reply:PP, Pp, Pp, pp. That would be b, c.
Reply:b.





PP = purple


Pp = purple


pP = purple


pp = white





Purple : white 3:1
Reply:Do you know how a Punnett square works? Look in your textbook.





P p


-----------------------


P | PP Pp


|


p | Pp pp





Resulting in a 25% chance of white-flowered plants and a 75% chance of purple ones. Therefore the answer is b. It can't be c. because a capital P means purple, so PP can't be a white-flowered plant.